C: casting to new structure vs casting to defined structure

my question is simple, does this

typedef struct {a;b;c;d;}bar;

has the same execution time as this?

((struct {a;b;c;d;}*)ANOTHERSTRUCTPOINTER)->a=1;
((struct {a;b;c;d;}*)ANOTHERSTRUCTPOINTER2)->a=1;
((struct {a;b;c;d;}*)ANOTHERSTRUCTPOINTERn)->a=1;

please mind that this is just an example, so don't just question the fact i didn't use an array


Yes, they mean the same thing and should compile into the same executable code.


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